Given a sorted array (sorted in non-decreasing order) of positive numbers, find the smallest positive integer value that cannot be represented as sum of elements of any subset of given set. Expected time complexity is O (n). Recommended: Please solve it on β PRACTICE β first, before moving on to the solution.
How to find the smallest positive number missing from an unsorted array?
You are given an unsorted array with both positive and negative elements. You have to find the smallest positive number missing from the array in O (n) time using constant extra space. You can modify the original array.
Which is the smallest of the four integers?
The (max-num) >> 31) operation captures the sign of the difference, which when multiplied by the second number yields the minimum value of the comparison. This comes from an old SQL coding trick from the days before there was a CASE WHEN construct in that language.
How to find all positive integers in an array?
We can build a hash table of all positive elements in the given array. Once the hash table is built. We can look in the hash table for all positive integers, starting from 1. As soon as we find a number which is not there in hash table, we return it.
How to find the Max non negative subarray?
Find out the maximum sub-array of non negative numbers from an array. The sub-array should be continuous. That is, a sub-array created by choosing the second and fourth element and skipping the third element is invalid. Maximum sub-array is defined in terms of the sum of the elements in the sub-array.
How to find the smallest subarray with sum greater than a given value?
Given an array of integers and a number x, find the smallest subarray with sum greater than the given value.
Which is the smallest element that cannot be represented?
We initialize the result as 1 (smallest possible outcome) and traverse the given array. Let the smallest element that cannot be represented by elements at indexes from 0 to (i-1) be βresβ, there are following two possibilities when we consider element at index i: