9 digit number puzzle. There is a 9 digit number. No digit are repeated and rightmost digit is divisible by 1 and right 2 digits is divisible by 2, right 3 digits is divisible by 3 and so on, finally the whole number is divisible by 9.
Is there a 9 digit number that is repeated?
There is a 9 digit number. No digit are repeated and rightmost digit is divisible by 1 and right 2 digits is divisible by 2, right 3 digits is divisible by 3 and so on, finally the whole number is divisible by 9. Can you find out the number?
How to arrange numbers in the right order?
Shuffle the numbers into the right order. Instructions: Choose a Level (3 to 10). The game board has blocks with numbers in it. Also there is a single “hole” that can be used for moving the blocks. The objective of the game is to order the numbers using the “hole” for temporary movement. Move blocks in a row by clicking on them.
Are there two pairs which add to 14?
There must be two pairs which add to 14. The only one is 8 + 6 so 1 cannot be in the corner. Guess 1 not in a corner, 9 must still be opposite to it. 8 and 6 must be in the adjacent corners. The other corners can be solved by the diagonal equations ( 2 and 4 ).
Which is number doubles when its last digit becomes its first digit?
Furthermore, if the new number has the same number of digits we would expect a to be an even number. We can try a = 2. The new number has to be double the original number. So we have a kind of multiplication problem. The new number has 2 (2) = 4 as its last digit.
How many four digit numbers are not all the same?
The program, which was about 50 statements in Visual Basic, checked all of 8991 four digit numbers from 1000 to 9999 where the digits were not all the same. The table below shows the results: every four digit number where the digits aren’t all equal reaches 6174 under Kaprekar’s process, and in at most seven steps.
Which is the number of 2 digit numbers we can make?
Using the counting principle, the number of 2 digit numbers that we can make using 4 digits is given by 4 × 3 = 12. The above problem is that of arranging 2 digits out of 4 in a specific order. This is also called permutating. The most important idea in permutations is that order is important. When you use the digits 3 and 4 to make a number,
What are the possible numbers if the last digit is 4?
If the last digit is 4, the possible numbers are 404, 314, 224 and 134. If the last digit is 5, the possible numbers are 505, 415, 325, 235 and 145. Note the pattern here – If the last digit is 1, there is only one number.
